-Answer for 13 is repulsive, do 14-17 -Show work and do not miss it on purpose i

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-Answer for 13 is repulsive, do 14-17

-Show work and do not miss it on purpose if not points will be awarded randomly

Assume that in interstellar space the distance between two protons is about .22 cm. The electric force between the two protons is attractive. repulsive. Calculate the electric force between these two protons. The value of the Coulomb constant is 9 Times 1 9 N m2/C2 and the elemental charge is 1.6 Times 1-19C Answer in units of N Calculate the gravitational force between these two protons. Newton's gravitational constant is 6.7 Times 1-11 N-m2/kg2 and the mass of the proton is 1.7 Times 1 -27 kg. Answer in units of N Three charges are arranged in the (x, y) plane as shown. What, is the magnitude of the resulting force on the 9 nC charge at the origin? The Coulomb constant is 8.98755 Times 1 9 N C2/m2. Answer in units of nN What angle does the resultant force on the 9 nC charge at the origin make with the positive x axis? Quadrant I lies between degree and 9 degree. quadrant II between between 9 degree and 18 degree, etc. Answer in units of degree

Explanation / Answer

13. repulsive force

14. force F = kq1q2/r^2

F v= 9e9*1.6*1.6*10^-38/0.0022*0.0022

F = 4.76*10^-23 N

15. F = Gm1m2/r^2

F = 6.67*10^-11 * 1.7*1.7*10^-54/0.0022^2

F = 3.987 *10^ -49 N

16. F1   due to charge o -8nC charge is F1 = 9e9 * 9*8/5^2 = 25.92 nN

F2 due to 9nC is F2 = 9e9 *9*9*10^-18/5^2 = 29.16 nN

Fnet^2 = F1^2 + F2^2

Fnet = 25.92^2 + 29.16^2

Fnet = 3.901 *10^-8 N

17. angle = tan^-1(29.16/25.92) = 48.36 deg with -x axis

or 180+ 48.36 = 228.36 deg from +ve x axis

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