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1)
the capacitor will behave like a wire
i=v(/r1+r4)=0.138 A:i(0)
2)
After very long time capcitor will behave like infinite resitance
i=V/(R1+R2+R3+R4)=0.077 A
3)Q=EC=1.632 mC
4)
just after the switch is closed Req=R1+R4+(R5//(R2+R3))=227.8 O
i=V/Req=0.105 A
5)charge after very long time does not depend on R value.same as part 3)=1.632 mC
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