A 28-kg box sits on the floor. The coefficient of static friction between box an

Question

A 28-kg box sits on the floor. The coefficient of static friction between box and floor is 0.44 and the coefficient o fkinetic friction is 0.33.

a) A pulling force of 150N is applied to the box at 25 degrees above horizontal. How fast will the box accelerate?

b) If the box is sliding across the floor at 2.5 m/s when all pushing or pulling forces are removed, how far will the box slide before stopping?

c) A pushing force is applied at an angle of 25 degrees below horizontal. How large must the force be to make the box move?

Explanation / Answer

a)
When the block is about to slide, the weight of the bucket and the sand is just equal to the maximum static friction that exists between the block and the table.
The 28.0 kg block weighs (28.0 kg)(9.80 m/s/s) = 274.4 N
First let's figure out the maximum static force:
Ffr(max) =

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.