Genes a & b have been reported to be 20 MU apart in fruit flies. You want to con

Question

Genes a & b have been reported to be 20 MU apart in fruit flies. You want to confirm this hypothesis. In order to test this hypothesis, you cross a true breeding double mutant male to a Wild Type female. As you expected the F1 progeny are all Wild Type. Now, YOU Want to map these genes, however you made a small error & you crossed 2 F1 individuals. The results of this cross show the following phenotypes: 816 Wild Types, 250 double mutants, 52 ''a'', & 42 ''b''. You tell your colleague, Dr. Skeptical, that these data support the hypothesis that there are 20 MU between genes a & b. He says they do not! Prove that you are correct.

Explanation / Answer

since, double mutants are 250 progeny and 'a' mutant and 'b' are 52 and 42 respectively, thus,

distance between a&b= 250+52+42/ toatl no. of progeny i.e. 1106 X 100

                               = 250 + 52+42/1160 X 100

                               = 344/1160X100

distance between a & b                              =29.65%

thus, Dr. skeptical is right the distance is more than 20 mu its 29.65 map units.

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