At a critical junction in a supercomputer, the current as a function of time is

Question

1. At a critical junction in a supercomputer, the current as a function of time is given as i(t) = 3t2-2t, where i is measured in milliamps and t is measured in seconds. How much charge passes through this critical junction during the interval 0 < t < 5.00 s?
   a.) 28.0 mCb.) 65.0 mCc.) 100 mCd.) 150 mC
   
   PLEASE SHOW WORK AND EXPLANATION!! I NEED TO KNOW HOW TO DO THE PROBLEM!

At a critical junction in a supercomputer, the current as a function of time is given as i(t) = 3t2-2t, where i is measured in milliamps and t is measured in seconds. How much charge passes through this critical junction during the interval 0 < t < 5.00 s?
a.) 28.0 mCb.) 65.0 mCc.) 100 mCd.) 150 mC

PLEASE SHOW WORK AND EXPLANATION!! I NEED TO KNOW HOW TO DO THE PROBLEM! At a critical junction in a supercomputer, the current as a function of time is given as i(t) = 3t2-2t, where i is measured in milliamps and t is measured in seconds. How much charge passes through this critical junction during the interval 0 < t < 5.00 s?

Explanation / Answer

di=dq/dt

dq=i*dt=t^3-t^2=125-25=100 mC

c is answer

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