The escape velocity of a bullet from the surface of planet Y is 1823 m/s. Calcul

Question

The escape velocity of a bullet from the surface of planet Y is 1823 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.47 times that of Y, and its radius is 0.839 times the radius of Y (in m/s). I need a final answer at the end please. Thanks. The escape velocity of a bullet from the surface of planet Y is 1823 m/s. Calculate the escape velocity from the surface of the planet X if the mass of planet X is 1.47 times that of Y, and its radius is 0.839 times the radius of Y (in m/s). I need a final answer at the end please. Thanks.

Explanation / Answer

Escape velocity is directly proportional to: sqrt (M / r)

Thus,

Vx / Vy = sqrt (Mx * Ry / My * Rx)

Thus,

Vx = sqrt ( 1.47 / 0.839) * 1823 = 2413 m/s would be escae velocity of planet X

Ans : 1823 m/s

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