In the circuit above, R 1 = 40 Ohms, R 2 = 65 ohms and R 3 = 115 ohms. The batte
ID: 3895855 • Letter: I
Question
In the circuit above, R1 = 40 Ohms, R2 = 65 ohms and R3 = 115 ohms. The battery voltage is ?Vb = 120 volts. Assume that the battery is ideal (internal resistance can be neglected).
What is the power dissipated in the resistor R3?
Give your answer in Watts to three digits
In the circuit above, R4 = R, R5 = 2.0 R, and R6 = 6.0 R, where R = 10 Ohms. The battery voltage is ?Vb = 6 volts, and assume that the battery is ideal (internal resistance can be neglected).
What is the difference in the power dissipated in resistors R5 and R6? In other words, what is P5
Explanation / Answer
current through R3=
120/(40+65+115)
=0.545A
SO POWER DELIVERED TO IT= I^2*R=34.214
IN SECOND CIRCUIT R4=10,R5=20, R6=60
i5=6/20
i6=6/60
P5-P6=1.8-0.6=1.2
i1/i2=5.75R/1.269R=4.53
SOLVING THE FOURTH CIRCUIT
0.4Vb=R3Vb/(R+RR3/(R+R3))
R3^2+22R3+4840=0
SO R3=-11 ohm
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