The normal force equals the magnitude of the gravitational force as a roller coa

Question

The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 49-m-diameter loop-the-loop.


What is the car's speed at the top?
The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 49-m-diameter loop-the-loop.


What is the car's speed at the top?
The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 49-m-diameter loop-the-loop.


What is the car's speed at the top?
The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 49-m-diameter loop-the-loop.


What is the car's speed at the top?
What is the car's speed at the top?

Explanation / Answer

r=49/2=24.5 m

2mg=m(v^2/r)

The masses cancel out.

2g=v^2/r

(2)(9.8)=v^2/24.5

v^2=480.9

v=21.93 m/s

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