show me the calculations. The ansewrs are c, d, b, c, d. Thanks. A 25- mu F capa

Question

show me the calculations. The ansewrs are c, d, b, c, d. Thanks.

A 25- mu F capacitor charged to 50 V and a capacitor C charged to 20 V are connected to each other, with the two positive plates connected and the two negative plates connected. The final potential difference across the 25- mu F capacitor is 36 V. What is the value of the capacitance of C? A 4.0-mF capacitor initially charged to 50 V and a 6.0-mF capacitor charged to 30 V are connected to each other with the positive plate of each connected to the negative plate of the other. What is the final charge on the 6.0-mF capacitor? When a capacitor has a charge of magnitude 80 mu C on each plate the potential difference across the plates is 16 V. How much energy is stored in this capacitor when the potential difference across its plates is 42 V? A 15- mu F capacitor and a 30- mu F capacitor are connected in series, and charged to a potential difference of 50 V. What is the resulting charge on the 30- mu F capacitor? A15- mu F capacitor and a 25- mu F capacitor are connected in parallel, and charged to a potential difference of 60 V. How much energy is then stored in this capacitor combination?

Explanation / Answer

net charge=25*50+20*C

assume C to be uF.

now they are connected in parallel.

so charges will also get added up.

now voltage across C also 36 Volts

so 36*(25+C)=25*50+20*C

C=21.875

so option c is corect answer.

Q26.

they are connected in parallel.

so net charge=4*50+6*30=380 mC

now let the common potnetial be V.

then V*(4+6)=380

V=38 volts

so charge on 6 mF=6*38=228 mC

so option e is correct.

Q27.

Q=C*V

so C=5 uF

energy=0.5*C*V^2=4410 uJ=4.41 mJ

option b is correct.

Q28.

as they are in series,they will have same charge.

so Q/15 + Q/30=50

Q=500 uC=0.5 mC

option c is correct.

Q29.

net capacitance=15+25=40 uF

energy=0.5*C*V^2=72 mJ

option d is correct

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