Using the same cycle as in the below question, compute the total HEAT input (in

Question

Using the same cycle as in the below question, compute the total HEAT input (in kJ) for this cycle.

(a) +20 kJ (b) +30 kJ (c) +40 kJ (d) +50 kJ (e) +60 kJ (f) None of the above.

The following figure shows the PV diagram for a monatomic idea gas undergoing an engine cycle consisting of an isochoric process from A(Va = 0.1 m3, PA = 100 kPA) - B(Vb = 0.1 m3, PB = 500 kPA),a linear process from B(Vb = 0.1 m3, PB = 500 kPA) -> C(Vc = 0.2 m3, Pc = 100 kPA),B to C and an isobaric process from C(Vc = 0.2 m3, Pc = 100 kPA) - A(Va = 0.1 m3, PA = 100 kPA).Assuming that the temperature of the ideal gas at point A is T = 300 K, compute the temperature of the ideal gas at the points B and C (Tb and To).Tb = 1600 K, Tc = 400 K TB = 1500 K, Tc = 600 K Tb = 1400 K, Tc = 700 K TB = 1300 K, Tc = 800 K Tb = 1200 K, Tc = 900 K (f) None of the Above.

Explanation / Answer

Work done = area under PV curve = (1/2)*0.1*(400,000) = 20,000 J = 20 kJ

Delta U = 0 for cyclic process,

using first law of thermodynamics, Q = W = +20kJ

a) 20 kJ

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