Consider a molecule in an ideal gas making a collision with the wall of a contai

Question

Consider a molecule in an ideal gas making a collision with the wall of a container. If the mass of the molecule is m and its speed is v, what is the change in momentum during the collision with the wall? (1/2)mv2 mv (1/2)mv mv2 2mv2 2mv Consider a molecule in an ideal gas making a collision with the wall of a container. If the mass of the molecule is m and its speed is v, what is the change in momentum during the collision with the wall? Consider a molecule in an ideal gas making a collision with the wall of a container. If the mass of the molecule is m and its speed is v, what is the change in momentum during the collision with the wall? (1/2)mv2 mv (1/2)mv mv2 2mv2 2mv (1/2)mv2 mv (1/2)mv mv2 2mv2 2mv

Explanation / Answer

change in momentum = Initial momentum - Final momentum

Initial momentum = mass * velocity = m*v =mv

Final momentum = -m*v = -mv ( because direction of molecule is reversed)

so,change in momentum = Initial momentum - Final momentum =mv - (-mv) =   2mv

so, so,change in momentum = 2mv is the answer

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