Consider the following copper cylinders(for each one the radius is given in term

Question

Consider the following copper cylinders(for each one the radius is given in terms of x= 2cm and the length is given in terms of l= 20 cm). If a wire is connected two batteries, the batteries are connected end to end (so the positive terminal of one battery is in contact with the negativeterminal of the other)
http://s683.photobucket.com/user/mahiletone/media/ScreenShot2014-03-24at20425AM.png.html?sort=3&o=0
a. Rank the resistance of the cylinders Largest Resistance = __________________________________________ = Smallest Resistance b. Rank the current through the cylinders Largest Current = _______________________________________________ = Smallest Current c. Rank the power dissipated by the cylinders Largest Power = ___________________________________________ ______ = Smallest Power
Consider the following copper cylinders(for each one the radius is given in terms of x= 2cm and the length is given in terms of l= 20 cm). If a wire is connected two batteries, the batteries are connected end to end (so the positive terminal of one battery is in contact with the negativeterminal of the other)
http://s683.photobucket.com/user/mahiletone/media/ScreenShot2014-03-24at20425AM.png.html?sort=3&o=0
a. Rank the resistance of the cylinders Largest Resistance = __________________________________________ = Smallest Resistance b. Rank the current through the cylinders Largest Current = _______________________________________________ = Smallest Current c. Rank the power dissipated by the cylinders Largest Power = ___________________________________________ ______ = Smallest Power
a. Rank the resistance of the cylinders Largest Resistance = __________________________________________ = Smallest Resistance b. Rank the current through the cylinders Largest Current = _______________________________________________ = Smallest Current c. Rank the power dissipated by the cylinders Largest Power = ___________________________________________ ______ = Smallest Power

Explanation / Answer

a) Resistance is proportional to l/A where l is length & A is area. & Area is pi*r^2

So, R is proportion to l/r^2

Hence

C>A=D>B=E

So, largest = C

Smallest = B&E

b)current proportional to V/R

Hence

E>B=D>A>C

largest = E

Smallest = C

C) power proportional to V*I

Hence,

E>D>B>A>C

largest = E

Smallest = C

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