2.) Consider an RL series circuit. R is still 881 ? and you measure L to be 773

Question

2.) Consider an RL series circuit. R is still 881 ? and you measure L to be 773 mH. You again set the signal generator output to produce a sinusouidal output with an amplitude of 1.85 V.

i) At what frequency will XL equal R?

ii) What will the voltage across the inductor be at this frequency?

We use the compound signal described above.

iii) Answer the following: What will the ratio of the amplitude of the voltage across the resistor due to the 49.1 Hz component of the signal to that of the 779 Hz component?

Explanation / Answer

Xinductive reactance XL = 2pifL = R

so frequency   f = 881/(2pi*0.773)

f = 181.48 Hz

current i = V/Z

impedence Z ^2 = R^2 + XL^2

Z^2 = 881^2 + (2*3.14*181.48*0.773)^2

XL = (2*3.14*181.48*0.773) = 881 ohms

Z = 1245.899 ohms

so current i = 1.85/1245.899 = 0.00148 A

b. V across inductor = VL = iXL = 0.00148 * 881 = 1.303 volts

c. when f = 49.5 Hz

XL = (2*3.14*49.5 *0.773) = 240.294 ohms

V acroos R = iR so it will not depend on f

so ratiop at given requencies = 1

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