A car starts from rest and accelerates around a flat curve of radius R = 31 m. T

Question

A car starts from rest and accelerates around a flat curve of radius R = 31 m. The tangential component of the car's acceleration remains constant at at = 3.4 m/s2, while the centripetal acceleration increases to keep the car on the curve as long as possible. The coefficient of friction between the tires and the road is ? = 0.94. What distance does the car travel around the curve before it begins to skid? (Be sure to include both the tangential and centripetal components of the acceleration.)

A) 38.1 m

B) 39.1 m

C) 31.1 m

D) 37.1 m

Please explain your answer. thank you

Explanation / Answer

max speed when u m g = sqrt( (mv^2/r)^2 + 3.4^2)

0.94*9.81 = sqrt( (v^2/31)^2 + 3.4^2)

v= at

0.94*9.81 = sqrt( (v^2/31)^2 + 3.4^2)

v=16.3 m/s

16.3^2 = 2*3.4*x

x = 39.1

so B)

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