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What is the output/outcome produced by this code segment? Pay attention to pre/p

ID: 3909771 • Letter: W

Question

What is the output/outcome produced by this code segment? Pay attention to pre/post ++

Assume input.txt has one line 3 5 7 9 11 13

Scanner infile = new Scanner (new file ( "input.txt" ) );

int [] arr = new int [10];

int count = 0;

while (infile.hasNextint () )

arr [++count] = infile.nextint ();

for ( int i=0; i<count; ++i)

System.out.print (arr[i] + " " );

the output will be = 0 3 5 7 9 11

Can you help me through the thought process to arrive at this output? Please be as detailed as possible. Note I have provided the output and mostly need an explantion

Explanation / Answer

Array indexing start at 0

in while loop while (infile.hasNextint () )

there is a pre increment of the variable count which is zero initially

SO when arr[++count] is executed it first increaments the count , which becomes 1 , then assign the array value at position 1 to the starting value read from the file which is 3

for second iteration

arr[2] = 5

for third iteration

arr[3]= 7

for fourth iteration

arr[4] = 9

for fifth iteration

arr[5] = 11

for sixth iteration

arr[6]=13;

now count is 6 after 6th iteration

Next line is for loop which loops from i =0 to i less than 6

since array element at position 0 (array indext starts from zero) is not assigned any values read from file as array values assigned from position one in while loop (because there is preincrement of the value count)

Values are printed from postion 0 to 5th position as loop will exit when i becomes 6 ,, hence value at position 6 is not displayed which is 13 at index 6

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