grep \'a*\' b? searches for 0 or more a\'s in two character file names that begi

Question

grep 'a*' b?

searches for 0 or more a's in two character file names that begin with b

Write a regular expression that will find all lines in a file named meetingMinutes that end in a question mark '?'

'?^'

What is the output of the following?

cat finalFile
1
12
123
1234
12345
bash-3.2$ grep '....' finalFile | wc -l

1

Which regular expression will find all lines in the file termApplications that contain valid birth month in the form: 1 letter month abbreviation followed by a 2 digit year, where the month abbreviation can only be: a, d, f, j, m , n, o, or s.
(So a97 and J04 would match, but not t45)

[adfjmnosADFJMNOS,0-9,0-9]

Explanation / Answer

Ans:

Q.2

option B - '?$'

Explanation:

grep '?$' command will print all the lines that end with '?'

The Regular expression $ will print all the lines that end with the input character or string

Example:

grep 's$'

output: All the lines that end with the character 's'

grep 'ing$'

output: All the lines that end with the string 'ing'

Q.3

option B - 2

Explanation:

-The regular expression '.' (dot) matches any character in place of it.

-If there are two dots, then grep command matches any two characters in place of it.

-wc command stands for "word count". This command counts the number of lines, words and total bytes

-wc -l command counts the number of lines

- grep '....' finalFile

The above command prints all the lines that contain at least four characters. When this command piped with wc -l prints the number of lines that contains atleast four characters(any).

-In the file f'inalFile' the number of lines that contains four characters are 2.

-They are 1234 and 12345

Example: grep '..' finalFile | wc -l

output: 4

grep '...' finalFile | wc -l   

output: 3

please like my answer if you are satisfied with it. thanks!

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