Based on below c program out put answers there two questions a) Is the displayed

Question

Based on below c program out put answers there two questions a) Is the displayed value for variable a what you think it should be? Explain the difference in displayed output for b and c in terms of the assigned data types. Be specific.
b, Explain the difference in displayed output for d when %f is used instead of %d. Be specific.








Code: #include int main char a-127,b; unsigned char c; int d-7697264 b- a*2; c a*2 printf( "a-0d b_0d c-Odln",a,b,c); printf("d-%d d %f n",d,d); printf("&d-;%sin",&d;); return 0 #include«stdio.h> int main() char a-127,b; unsigned char c; int d-7697264; b a*2 C- a 2 printf( "a %d b2%d c2%d " , a,b,c); printf("d-%d d %f ",d,d); printf("&d-;%s ",&d;); return ?; Output: hadoop@ubuntu: $ /a.out a 127 b -2 c 254 &d-psu;

Explanation / Answer

a) In this program variable a is declared as character.

But initialized with integer 127. In c, a integer assigned to the character variable is a ASCII code. Here 127 ASCII code is equal to delete. So, the actual value of c is "delete" but c is unable hold the value.

Here b is declared as char and c is declared as unsigned char.

signed typed values are stored in 2's complement internally, but unsigned typed values are stored normally. So , the value of b is 127*2=254 that is in 2's complement=-2 and the value of c is 254 as the output. The basic difference b/w the values b and c is ineternal representation of values of char and unsigned char.

b) The variable d is declared and initialized with integer data.

     %d - is specified to display the content of inetger variable.

    %f   -is used to to display the content of float or double variable.

if %d is specified the printf() expects the next argument is integer.So, the %d specifier prints the value of variable d correctly.

Here %f is specified for integer variable d, but the printf() expects the float or double type variable argument. So, the action is undefined and prints 0.000000 value.

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