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5. [10 marks] Assume that fifteen 800-bps terminals, a number of 400-bps termina

ID: 3916123 • Letter: 5

Question

5. [10 marks] Assume that fifteen 800-bps terminals, a number of 400-bps terminals, and thirty 200- bps terminals are to be time-multiplexed in a character-interleaved format over a 20,800 bps synchronous line. All the terminals are asynchronous and send 10 bits/character (7 bits of data, 1 parity bit, 1 start bit and 1 stop bit). In the synchronous frame, one synchronization character start the frame that can be no longer than 200 characters (including synchronization characters). Define following multiplexer requirements for maximum efficiency: Determine the number of bits in characters received from the terminals that are saved in the multiplexer's frame. Determine the number of 400-bps terminals that can be accommodated. a. b.

Explanation / Answer

a> Asynchronous transmission will transmit as streams. Here 200 characters are to be included and with additional bits of 10(7bits for data, 1 bit for parity, 1bit for start, 1 bit for stop)2 bits in characters

So bits required=200/10=2

2bits per character is used

b> In total there are 20800 bps channels, among them 15 -800bps channel ie in total 12000bps channels. then there are 30-200bps channels in total 6000bps channels. By subtracting these from total number of channels we will get28-400bps channels

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