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(1) The signal power for a particular class of network wiring is 8733.26 dB and

ID: 3918727 • Letter: #

Question

(1) The signal power for a particular class of network wiring is 8733.26 dB and the noise rating at that particular signal strength at 100MHz is 41.8 dB . Find the signal - to - noise atio for this conductor.

Hint: apply this formula   

  Signal - to - Noise Ratio ( dB ) = 10 log 10 ( signal strength dB / noise rating dB )

( 2 ) The signal - to - noise rating for the network wiring in Part a is 9.5 dB and the noise rating is 36.9 dB when a 200MHz signal is transmitted. What is the signal strength?

Hint: apply this formula   

  Signal - to - Noise Ratio ( dB ) = 10 log 10 ( signal strength dB / noise rating dB )

(3) The signal power for a particular class of network wiring is 2898 dB and the noise rating at that particular signal strength at 100MHz is 40 dB . Find the signal - to - noise ratio for this conductor.   

Explanation / Answer

1) Signal Strength(in dB)=8733.26 dB

Noise Rating(in dB)=41.8 dB

Since, Signal - to - Noise Ratio ( dB ) = 10 log10 ( signal strength dB / noise rating dB )

Therefore, Signal-to-noise ratio(SNR)=10 log10 (8733.26/41.8)

=23.2 dB

2) Signal - to - Noise Ratio(SNR)=9.5 dB

Therefore,

9.5 dB=10 log10 (Signal Strength dB/36.9 dB)

Signal strength=328.8 dB

3)Signal Strength(in dB)=2898 dB

Noise Rating(in dB)=40 dB

Since,  Signal - to - Noise Ratio ( dB ) = 10 log10 ( signal strength dB / noise rating dB )

Therefore, Signal-to-noise ratio(SNR)=10 log10 (2898/40)

=1.86 dB