Helper 4: Getting the user\'s guess [7 marks]¶ get_guessed_word(word_to_guess, l

Question

Helper 4: Getting the user's guess [7 marks]¶

get_guessed_word(word_to_guess, letters_guessed): takes two parameters: a string, word_to_guess, and a list of letter, letters_guessed. This function returns a string that is comprised of letters and underscores, spaces are optional, based on what letters in letters_guessed are in word_to_guess. This shouldn't be too different from isGoodGuess!

For readability separate each underscore with a space: _ _ _ _. Without a space it is hard to distinguish whether ____ is four elements or three ___. Adding the space helps to improve your program's usability.

def get_guessed_word(word_to_guess, letters_guessed):
    """ Provide function docstring
    """

    return "YOUR ANSWER HERE"

Test get_guessed_word() to verify that the created string correctly presents the guessed letters in word_to_guess

def a4():
    guess1 = get_guessed_word('apple', ['i'])
    guess2 = get_guessed_word('apple', ['l', 'i', 'k', 't', 'r', 's'])
    guess3 = get_guessed_word('apple', ['a', 'l', 'k', 'p', 'r', 'e'])
   
    if guess1 == '_ _ _ _ _' and guess2 == '_ _ _ l_' and guess3 == 'apple':
        return 'Correct'
    else:
        return 'Wrong'
   
a4()

Explanation / Answer

def get_guessed_word(word_to_guess, letters_guessed): result = '' for i in range(len(word_to_guess)): ch = word_to_guess[i] if ch in letters_guessed: result += ch else: result += '_' if i != len(word_to_guess) - 1: result += ' ' return result def a4(): guess1 = get_guessed_word('apple', ['i']) guess2 = get_guessed_word('apple', ['l', 'i', 'k', 't', 'r', 's']) guess3 = get_guessed_word('apple', ['a', 'l', 'k', 'p', 'r', 'e']) if guess1 == '_ _ _ _ _' and guess2 == '_ _ _ l_' and guess3 == 'apple': return 'Correct' else: return 'Wrong' print(a4())

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.