Provide the prototype for a function called my_str_n_cpy () that accepts two poi

Question

Provide the prototype for a function called my_str_n_cpy () that accepts two pointers to characters, which represent addresses to the beginning of the destination buffer/array and the source buffer array, and an integer n. The function copies a total of n characters from the source buffer into the destination buffer. If the null character is encountered in the source buffer before n characters have been copied, then the destination character should be filled in with the null character until n is reached. The function must return a pointer to the beginning of the destination buffer.

Explanation / Answer

//function prototype
char *my_str_n_cpy (char *destination, char *source, int n);

//function defition

/*
The function my_str_n_cpy that takes two pointers destination, source
and integer n value and copies the source to destination for given size
*/
char *my_str_n_cpy (char *destination, char *source, int n)
{
   int i = 0;
   int source_size = 0;
   int dest_size = 0;
   //get size of source
   while (source[i] != NULL)
   {
       source_size++;
       i++;
   }

   i=0;
   //get size of destination
   while (destination[i] != '')
   {
       dest_size++;
       i++;
   }

   //copy from source to destination
   for (i = 0; i <n; i++,dest_size++)
   {      
       if (source[i] != '')      
           destination[dest_size] = source[i];          
       else      
           break;

   }
  
   //return destination pointer
   return destination;
}

------------------------------------------------------------------------------------------------------------------

//Test program

#include<stdio.h>
#include<conio.h>
//function prototype
char *my_str_n_cpy (char *destination, char *source, int n);
int main()
{

   //intialize two c-strings
   char source[50]="my_string";
   char dest[50]="";

   //calling fucntion
   char *result=my_str_n_cpy(dest,source,4);

   int i=0;
   //print result to console
   while (result[i] != NULL)
   {
       printf("%c", result[i]);
       i++;
   }

   getch();
   return 0;
}
/*
The function my_str_n_cpy that takes two pointers destination, source
and integer n value and copies the source to destination for given size
*/
char *my_str_n_cpy (char *destination, char *source, int n)
{
   int i = 0;
   int source_size = 0;
   int dest_size = 0;
   //get size of source
   while (source[i] != NULL)
   {
       source_size++;
       i++;
   }

   i=0;
   //get size of destination
   while (destination[i] != '')
   {
       dest_size++;
       i++;
   }

   //copy from source to destination
   for (i = 0; i <n; i++,dest_size++)
   {      
       if (source[i] != '')      
           destination[dest_size] = source[i];          
       else      
           break;

   }
  
   //return destination pointer
   return destination;
}

Sample Output:

my_s

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