1. Final assembly 2. Wheel assembly line (2 per finished bicycle) 3. Frame assem
ID: 393408 • Letter: 1
Question
1. Final assembly 2. Wheel assembly line (2 per finished bicycle) 3. Frame assembly line (1 per finished bicycle) Business Data: Annual demand (forecast) for finished motorcycles: 75,000 Work days in the year 250 Shifts worked 2 Actual process times: Final assembly: 8 minutes (each) Wheel assembly: 6 minutes (each) Frame assembly: 5 minutes (each) (1 person at 1 frame assembly station can assemble 1 frame in 5 minutes) #of Production | AnnualDaily Takt stations Line Demand Demand Time needed Final Assem Wheel Assembly Frame Assembly 75000 9 30 31 32 34Explanation / Answer
Explanation
Wheel assembly= 2*final assembly= 150000
Frame assembly= final assembly= 75000
Daily demand= annual demand / work days
Assuming 8 hour shifts for twice in a day. (Note: if shift is not 8 hours please change calculation accordingly)
That is 16 working hours daily, therefore,
Takt = (16*60)/daily demand
Total labour content of station = process time of station
Answer:
the target manpower=no. of station= total labour content/ TAKT time
therefore, no. of station needed for
Annual demand
Daily demand
Takt time
# of stations needed
Final assembly
75000
300
3.2
2.5
Wheel assembly
150000
600
1.6
3.8
Frame assembly
75000
300
3.2
1.6
Annual demand
Daily demand
Takt time
# of stations needed
Final assembly
75000
300
3.2
2.5
Wheel assembly
150000
600
1.6
3.8
Frame assembly
75000
300
3.2
1.6
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