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6) Shown below is a 240 base pair segment of an E. coli gene. It includes the pr

ID: 40116 • Letter: 6

Question

6) Shown below is a 240 base pair segment of an E. coli gene. It includes the promoter and the first codon of the gene. The sequences of both strands of the DNA duplex are shown here. The top strand reads 5' to 3' left to right (1 to 240); the bottom, complimentary, strand reads 5' to 3' right to left (240 to 1).

i) Open up the first 60 bases as a replication fork. Show the primer location and their polarities for the leading and lagging strands.

As you know, DNA synthesis requires a primer, which is synthesized by a primase. Suppose you want to replicate the DNA in this replication fork, what would be the 5

6) Shown below is a 240 base pair segment of an E. coli gene. It includes the promoter and the first codon of the gene. The sequences of both strands of the DNA duplex are shown here. The top strand reads 5' to 3' left to right (1 to 240); the bottom, complimentary, strand reads 5' to 3' right to left (240 to 1). i) Open up the first 60 bases as a replication fork. Show the primer location and their polarities for the leading and lagging strands. As you know, DNA synthesis requires a primer, which is synthesized by a primase. Suppose you want to replicate the DNA in this replication fork, what would be the 5?? to 3?? sequence of a primer (write about 10 bases) and its orientation for the top and the bottom strands. ii) RNA polymerase binds to the sequence (underlined above) and shown below. Once bound, RNA polymerase starts making mRNA at the 6th nucleotide after the end of the sequence (at position a, also underlined above). Synthesis of the mRNA proceeds 5' to 3' left to right on the sequence above. Write the sequence of the first 10 nucleotides of the resulting mRNA.

Explanation / Answer

E.coli ;

240 bp segment , has promoter and first codon   has two starnds leading strand 5'to 3' and lagging stand 3'to 5' .

answer for the i ;

PRIMER FOR LEADING STRAND ; 3' TACACTCAAT 5'

PRIMERS LOCATION LAGGING STARND ; 5' ATGCTCGGCCT 3'

ANSWER FOR THE II ;

RNA POLYMERASE ACTION ; it creates the short RNA sequences called primer mRNA for the single stand DNA it requires the promoter like sequences.

so for the leading strand;

the binding site is   5' CTTTACACTTT 3'

SO FROM THE 6 NUCLOTIDE THE RNA SYNTHESIS WILL BE 3' AUGAAAUACGAA 5,' { AS t RNA HAS SEQUENCE FOR 3'TO 5' , STARING CODON WILL BE AUG -CODES FOR METHIONINE]

FOR LAGGING STARND

RNA BINDING SEQUENCE;

3'GAAATGTGAAA 5' - IN THIS RNA POLYMERASE START S FROM AAT REGION

from mRNA will   be 3; AUUUCGGACCCC 5' , HERE AUU   act as a start codon

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