Suzy, a bartender, can serve drinks at the average rate of one every 35 sec. Dur

Question

Suzy, a bartender, can serve drinks at the average rate of one every 35 sec. During a hot evening recently, the bar was particularly busy and every 45 sec someone was at the bar asking for a drink.

a.assuming that everyone in the bar drank at the same rate and that suzy served people on a first come, first served basis, how long would you expect to have to wait for a drink?

b. how many people would you expect to be waiting for drinks?

c. What is the probability that three or more people are waiting for drinks?

d.What is the utilization rate of the bartender?

need calculations with answer

Explanation / Answer

ANSWER THIS WILL HELP YOU Well, just walk through it. 1) You'll need Traffic intensity: ?=?? 2) This gives immediately the complete probability distribution of the queue. p(n)=?n?(1??) 3) Out pops, p(nooneinthequeue)=p(0)=1?? 4) Easily then, p(3ormoreinthequeue)=1?[p(0)+p(1)=p(2)] 5) How many can you expect to find in line: [tex]Mean;queue;length = E[queue;pdf;variable] = rac{ ho}{1- ho}[/tex] 6) It seems logical that one could expect to wait (Mean Service Time)*(Expected Number of Folks in Line)

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