Chi Square Analysis question (Genetics) To assess Mendel\'s law of segregation u
ID: 41891 • Letter: C
Question
Chi Square Analysis question (Genetics)
To assess Mendel's law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (ss). The heterozygous tall (Ss) were crossed to produce the two sets of F2 data as follows: Using chi-square analysis, analyze the results for both data sets. Calculate X^2 values, and estimate the p values in both cases. From the analysis in part (a), what can you conclude about the importance of generating large data sets in experimental settings?Explanation / Answer
a.
Phenotype
O
E
(O-E)
(O-E)2
(O-E)2/E
Tall
30
26.25
3.75
14.0625
0.536
Short
5
8.75
-3.75
14.0625
1.607
2.14
P = between 2 and 0.05. The null hypothesis is accepted as the difference between the expected and observed values is less.
Phenotype
O
E
(O-E)
(O-E)2
(O-E)2/E
Tall
300
262.5
37.5
1406.25
5.35
Short
50
87.5
-37.5
1406.25
16.07
21.42
P = less than 0.001. Therefore, null hypothesis is rejected since there is a significant difference between the observed and expected.
b.
As sample size increases, it leads to different results and provides more confidence on the values obtained.
Phenotype
O
E
(O-E)
(O-E)2
(O-E)2/E
Tall
30
26.25
3.75
14.0625
0.536
Short
5
8.75
-3.75
14.0625
1.607
2.14
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