1. Suppose that a product has three parts, each of which must work in order for
ID: 433783 • Letter: 1
Question
1. Suppose that a product has three parts, each of which must work in order for the product to function. The reliabilities of the parts are.898, .933, and .946, respectively. What is the reliability of the product? 2. Suppose that a product has two parts, both of which must be working in order for the product to function. The reliability of the first part is .83, and the reliability of the second part is.82 In addition, the second part comes with a backup that is 50% reliable. What is the overall reliability of the product? 3 As a design engineer you need to obtain 99.9% reliability. The first part has a reliability factor of 99.99%. What level of reliability does the series part require to achieve 99.9% overall reliability? 4 The design engineer in question #3 needs to improve the overall system reliability by adding another part in parallel to the unit calculated in question #3. The objective is to achieve an overall system reliability of 99.95%. What reliability must the parallel part have to meet this . Inspectors want to develop process control charts to measure the weight of crates of wood. Data (in pounds) from three samples are: Sample r Crate 2 26 20 26 26 30 26 26 26 (a) What is the upper control limit for the R chart? (b) What is the lower control limit for the R chart (c) What is the upper control limit for the x-bar chart? (d) What is the lower control limit for the x-bar chart? (e) Is the process in a state of control? If not, why not? 6. Eight samples of n- 50 were taken by an operator at a workstation in a production process. The number of defective items in cach sample was recorded as follows. Number of Sampl Defests 10 12 (a) Management wants to develop a p-chart. (b) Is the process in a state of control? What are the control limits?Explanation / Answer
1.
2.
3.
4.
Hence new component in parallel should have R = 99.5%
1 As each must work for product to function, so they are in series R1 0.898 R2 0.933 R3 0.946 Rnet = R1*R2*R3 0.792591Related Questions
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