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Given the following amount of work in seconds required at each station. A 38 J 3

ID: 436727 • Letter: G

Question

Given the following amount of work in seconds required at each station.

A         38                    J           32                    X         22

B         34                    K         30                    Y         18                                           

C         35                    L          34                    Z          20

What is the possible daily output of this “process” if 8 hours of processing time is available each day?
b. Given your output rate in part a, what is the efficiency of the process?
c. What is the flow time of the process?

Explanation / Answer

First add all the times together. You get 263 seconds per chair. Now, in 8 hours there are 60 minutes per hour, and 60 seconds per minute. So in 8 hours there are 28800 seconds. Now divide the 28800 seconds in 8 hours by the 263 seconds it takes to make one chair. You get 109.5, and since you wouldn't count 1/2 a chair, your answer for (a) : 109 chairs per day is possible (b) : I have no idea what throughput time means. As grampedo pointed out, the production is only as fast as the slowest station. However, it's not station C, it's station A that is the slowest. So 28800 seconds in 8 hours / 38 seconds, =757.89 chairs, =757 chairs possible.

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