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A manager wants to estimate the remaining time that will be needed to complete a

ID: 449385 • Letter: A

Question

A manager wants to estimate the remaining time that will be needed to complete a five-unit job. The initial unit of the job required 20 hours, and the work has a learning percentage of 77. Estimate the total time remaining to complete the job. (Round your intermediate calculations to 4 decimal places. Round your "Estimated time" and final answer to 2 decimal places.)


A manager wants to estimate the remaining time that will be needed to complete a five-unit job. The initial unit of the job required 20 hours, and the work has a learning percentage of 77. Estimate the total time remaining to complete the job. (Round your intermediate calculations to 4 decimal places. Round your "Estimated time" and final answer to 2 decimal places.)

Explanation / Answer

Time taken for nth unit under learning curve is an^b where a the time taken for first unit b is calculated as [log (learning curve rate)- log 100] / log 2 b at 77% learning curve rate = (log 77 - log 100) / log 2 = 1.8865 - 2 / 0.3010 = -0.3771 Time for each unit is calculated as Unit Total Time 1 20*1^-0.3771 20.00 2 20*2^-0.3771 15.40 3 20*3^-0.3771 13.22 4 20*4^-0.3771 11.86 5 20*5^-0.3771 10.90 71.37 Total Time = 71.37 hours for 5 units Incremental time = 71.37 - 20 = 51.37 hours Hence the answer is 51.37 hours This can also be calculated as under Using b, finding the Learning Curve factors for 5 units Learning Curve factor is the summation of n^b, where n stands for units =1^-0.3771 1.0000 =2^-0.3771 0.7700 =3^-0.3771 0.6608 =4^-0.3771 0.5929 =5^-0.3771 0.5450 3.5687 Multiplying the factor with first unit time, we get total time = 3.5687*20 = 71.37 hours So incremental time for 4 units = 71.37 hours -20 hours = 51.37 hours Time taken for nth unit under learning curve is an^b where a the time taken for first unit b is calculated as [log (learning curve rate)- log 100] / log 2 b at 77% learning curve rate = (log 77 - log 100) / log 2 = 1.8865 - 2 / 0.3010 = -0.3771 Time for each unit is calculated as Unit Total Time 1 20*1^-0.3771 20.00 2 20*2^-0.3771 15.40 3 20*3^-0.3771 13.22 4 20*4^-0.3771 11.86 5 20*5^-0.3771 10.90 71.37 Total Time = 71.37 hours for 5 units Incremental time = 71.37 - 20 = 51.37 hours Hence the answer is 51.37 hours This can also be calculated as under Using b, finding the Learning Curve factors for 5 units Learning Curve factor is the summation of n^b, where n stands for units =1^-0.3771 1.0000 =2^-0.3771 0.7700 =3^-0.3771 0.6608 =4^-0.3771 0.5929 =5^-0.3771 0.5450 3.5687 Multiplying the factor with first unit time, we get total time = 3.5687*20 = 71.37 hours So incremental time for 4 units = 71.37 hours -20 hours = 51.37 hours

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