If it took 563 minutes to complete a hospital\'s first cornea transplant, and th

Question

If it took 563 minutes to complete a hospital's first cornea transplant, and the hospital uses a 90% learning rate, then, using Table E.3, the cumulative time to complete

a) the first 3 transplants in minutes

b) 6 transplants in minutes

c) 8 transplants in minutes

d) 16 transplants in minutes

Table E.3

Please show work.

80% 80% 85% 85% 90% 90% Unit Number Unit Time Total Time Unit Time Total Time Unit Time Total Time 3 .702 2.502 .773 2.623 .846 2.746 6 .562 4.299 .657 4.688 .762 5.101 8 .512 5.346 .614 5.936 .729 6.574 16 .410 8.920 .522 10.383 .656 12.040

Explanation / Answer

The time taken to complete the 3rd unit will be

T3 = T1C, where C is the coefficient for the unit.

T3 = 563 x 0.846 = 476.298 minutes

Cumulatively for 3 transplants

T = 563 x 2.746 = 1545.998 minutes

For the 6th unit

T6 = 563 x 0.762 = 429.006 minutes

Cumulatively for 6 transplants

T = 563 x 5.101 = 2871.863 minutes

For the 8th unit

T8 = 563 x 0.729 = 410.427 minutes

Cumulatively for 8 transplants

T = 563 x 6.574 = 3701.162 minutes

For the 16th unit

T16 = 563 x 0.656 = 369.328 minutes

Cumulatively for 16 transplants

T = 563 x 12.04 = 6778.52 minutes

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.