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Her staff also has estimated the normal and crash times and costs for tasks invo

ID: 465539 • Letter: H

Question

Her staff also has estimated the normal and crash times and costs for tasks involved in the breakdown. The information is summarized below. The campaign starts on 4/1/2016.

Task

Time Estimates (Weeks)

Cost Estimates ($)

Normal

Crash

Normal

Crash

A1

6

4

5,000

10,000

B2

3

3

4,000

4,000

C

10

8

4,000

7,000

D

4

2

1,000

2,000

E

2

1

1,000

2,000

F

3

1

4,000

7,600

G

5

4

7,000

12,000

H

7

5

8,000

14,000

I

2

2

1,200

1,200

J

4

3

5,000

5,800

K

8

6

13,000

15,000

L

5

5

6,000

6,000

M

4

4

2,500

2,500

1 Task A can be crashed by 2 weeks at an additional cost of $5000 ($2,500/week).

2 Task B cannot be crashed.

Ann has to campaign for 35 weeks. Determine the total cost needed to complete the project with Ann’s time constraint.

Hint: Only the tasks in CP can be crashed to shorten the project duration. Consider the tasks with more days with less cost to crash.

Complete the attached answer sheet, save it as Your Name Assignment 10, and submit it with your MPP file in Assignment 10 area

Name:_______________

Answers:

Question 1.

Critical Path:

Duration:

Finish date:

Question 2

Total normal project cost:

$______________

Question 3

Tasks that should be crashed and additional cost:

Task

Weeks to cut

Cost

C.P. after crash

Question 4

Total crashed project cost:

$_____________

Question 5: Your MPP file

Task

Time Estimates (Weeks)

Cost Estimates ($)

Normal

Crash

Normal

Crash

A1

6

4

5,000

10,000

B2

3

3

4,000

4,000

C

10

8

4,000

7,000

D

4

2

1,000

2,000

E

2

1

1,000

2,000

F

3

1

4,000

7,600

G

5

4

7,000

12,000

H

7

5

8,000

14,000

I

2

2

1,200

1,200

J

4

3

5,000

5,800

K

8

6

13,000

15,000

L

5

5

6,000

6,000

M

4

4

2,500

2,500

Explanation / Answer

Step 1: Determine Critical Path

To determine critical path first identify the Earliest and Latest start and Finish times:

Task

Normal

ES

EF

LS

LF

Slack

Critical Activities

A

6

0

6

0

6

0

y

B

3

0

3

9

12

9

C

10

6

16

6

16

0

y

D

4

3

7

12

16

9

E

2

16

18

19

21

3

F

3

16

19

16

19

0

y

G

5

18

23

21

26

3

H

7

19

26

19

26

0

y

I

2

26

28

26

28

0

y

J

4

28

32

31

35

3

K

8

28

36

28

36

0

y

L

5

32

37

35

40

3

M

4

36

40

36

40

0

y

Project Completion (weeks)

40

The Project completion time = 40 weeks

Critical path: Activities for which slack = LF – EF is zero are critical activities, and the path formed by this activities in critical path.

Critical path is A-C-F-H-I-K-M, duration of critical path is 40 weeks.

Total cost of project without crashing = $61,700.

Crashing of Project

For crashing first determine Allowable crashing weeks and crashing cost per week.

Allowable Crashing = Normal Time – Crash Time

Crashing Cost per week = (Crash Cost – Normal Cost)/Allowable crashing.

Time Estimates (Weeks)

Cost Estimates ($)

Allowable crashing weeks

Crashing cost per week

Task

Normal

Crash

Normal

Crash

A

6

4

5,000

10,000

2

2500

B

3

3

4,000

4,000

0

0

C

10

8

4,000

7,000

2

1500

D

4

2

1,000

2,000

2

500

E

2

1

1,000

2,000

1

1000

F

3

1

4,000

7,600

2

1800

G

5

4

7,000

12,000

1

5000

H

7

5

8,000

14,000

2

3000

I

2

2

1,200

1,200

0

0

J

4

3

5,000

5,800

1

800

K

8

6

13,000

15,000

2

1000

L

5

5

6,000

6,000

0

0

M

4

4

2,500

2,500

0

0

Total Normal Cost

$61,700

For crashing, only critical activities are considered for reduction in completion period.

From the critical activities least crashing cost per week is for critical activity K, that is $1000 per week and allowable reduction is by 2 weeks.

By crashing the activity K to 6 weeks, the critical path is same, A-C-F-H-I-K-M with new path duration of 38 weeks.

From the critical activities least crashing cost per week is for critical activity C, that is $1500 and allowable reduction is by 2 weeks.

By crashing the activity C to 8 weeks, the critical path is same, A-C-F-H-I-K-M with new path duration of 36 weeks.

From the critical activities least crashing cost per week is for critical activity F, that is $1800 and allowable reduction is by 2 weeks.

By crashing the activity F to 2 weeks, the critical path is same, A-C-F-H-I-K-M with new path duration of 35 weeks.

Thus, after crashing the activities K, C and F the project completion time is 35 weeks which is desired completion time by Ann. So stop crashing ahead.

The crashing is reviesed in the earliest and Latest time calculation as follows:

Task

Normal

ES

EF

LS

LF

Slack

Critical Activities

A

6

0

6

0

6

0

y

B

3

0

3

7

10

7

C

8

6

14

6

14

0

y

D

4

3

7

10

14

7

E

2

14

16

16

18

2

F

2

14

16

14

16

0

y

G

5

16

21

18

23

2

H

7

16

23

16

23

0

y

I

2

23

25

23

25

0

y

J

4

25

29

26

30

1

K

6

25

31

25

31

0

y

L

5

29

34

30

35

1

M

4

31

35

31

35

0

y

Project Completion time

35

Answers:

Question 1.

Critical Path:

A-C-F-H-I-K-M

Duration:

40 weeks

Finish date:

40 weeks

Question 2

Total normal project cost:

$61,700

Question 3

Tasks that should be crashed and additional cost:

Task

Weeks to cut

Cost

C.P. after crash

K

2

1000 x 2 = 2000

A-C-F-H-I-K-M

C

2

1500 x 2 = 3000

  A-C-F-H-I-K-M

F

1

1800 x 1 = 1800

  A-C-F-H-I-K-M

Question 4

Total crashed project cost:

$ 61,700 + $2000 + $3000 + $1800 = $68,500

Task

Normal

ES

EF

LS

LF

Slack

Critical Activities

A

6

0

6

0

6

0

y

B

3

0

3

9

12

9

C

10

6

16

6

16

0

y

D

4

3

7

12

16

9

E

2

16

18

19

21

3

F

3

16

19

16

19

0

y

G

5

18

23

21

26

3

H

7

19

26

19

26

0

y

I

2

26

28

26

28

0

y

J

4

28

32

31

35

3

K

8

28

36

28

36

0

y

L

5

32

37

35

40

3

M

4

36

40

36

40

0

y

Project Completion (weeks)

40

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