Balancing equations lab Materials required: Four rubber balloons(Spherical shape

Question

Balancing equations lab

Materials required:

Four rubber balloons(Spherical shape).

White Vinegar

Baking soda(NaHCO3)

Pencil

Funnel.

Procedure :

1. Into a balloon 1, 1/4 th of a level tea spoon of baking soda. Place 1/2 of a level teaspoon of baking soda in balon-2.Place 3/4 of a level teaspoon of baking soda in ballon-3 and one level teaspoon of baking soda in ballon-4.

2. Measure 2 table spoons of vinegar and quickly pour it through the funnel into one of the balloons. very quickly remove the funnel and tie off the balloon opening.set this balloon aside.Repeat the procedure with the rest of the balloons.

3. Compare the size of each balloon and rank them from the smallest to largest volume.

Readings are as follows :

Experiment 1: NaHCO3= 0.0095238 mol CH3COOH=0.025 mol CO2=135.2 mL=0.1352 L=0.06898 mol

Experiment 2: NaHCO3=0.01905 mol CH3COOH=0.025 mol CO2 = 233.63 mL=0.23363 L=0.1192 mol

Experiment 3: NaHCO3= 2.4 g=0.02857143 mol CH3COOH =0.025 mol CO2=297.03 mL=0.29703 L=0.151546 mol

Experiment 4: NaHCO3=0.0381 mol CH3COOH=0.025 mol CO2=456.3 mL=0.4563 L=0.233 mol

My questions are as follows:

1. Why is comparing moles of reactants without using the balanced equation not the proper way to determine the limiting reactant??

2. Why did one reaction situation produce the gretest volume of Co2??

Explanation / Answer

For Question 1:

Take an example below reaction

CH4 + 2O2 -------> CO2 + 2H2O

Let us have 1.5 moles of CH4 and 2 moles of O2, by your case since moles of O2 are higher than CH4, then CH4 must be a limiting reagent

But in reality that is not correct, since 1 mole of CH4 reacts with 2 moles of O2 to produce CO2 and H2O

Hence 1.5 moles will require 3 moles of O2 and since we have only 2 moles of O2, hence O2 is the limiting reagent in the raction and not CH4

Hence the balancing equation is a must in order to find limiting reagent

For Question 2:

NaHCO3 + CH3COOH ----------- CH3COONa + H2O + CO2

Hence the last reaction produce maximum since the limiting reagent quantity is maximum in the last Experiment 4 as compared to other experiments

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