99.999% of the acid to be neutralized? (b) Under normal laboratory conditions, w

Question

99.999% of the acid to be neutralized? (b) Under normal laboratory conditions, would you expec the rate of the acid-base neutralization to be limited by the rate of the reaction or by the speed of mixing? 12.125 The reaction 2 Nog) o20g)- 2 No, (e) has the third order rate law: rate k[NO]2[O2], where 25 M law is the condition that Nol- ol, the negated ate 8 kt ([O2lo) [O2] What are the concentrations of NO, O2, and NO2 after and [O2] 0.0100 M? 12.126 Consider the following data for the gas-phase decomposi- tion of NO2 2 NO2 (g) 2Nog) O2 (g)

Explanation / Answer

Using the integrated rate law,

1/[O2]^2 = 8kt + 1/([O2]o])^2

with,

[O2]o = 0.01 M

k = 25 M-2.s-1

t = 100s

we get,

1/[O2]^2 = 8 x 25 x 100 + 1/(0.01)^2

final concentration of [O2] after 100s = 0.0058 M

The change in concentration of O2 is = 0.01 - 0.0058 = 0.0042 M

Now,

[NO] = 2[O2]

initial [NO] = 0.02 M

final concentration of NO = 0.02 - 2 x 0.0042 = 0.0116 M

Related Questions

Navigate

• Browse (All)
• Browse 9
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.