Alicia koBez seaden IA Experiment 11 Advance Study Assignmont: The Atomic Spectr

Question

Alicia koBez seaden IA Experiment 11 Advance Study Assignmont: The Atomic Spectrum of Hydrogen I. Found in the gas phase, the beryllium trication (triply charged positive, or +3. ion). Be has an energy level formula analogous to that of the hydrogen atom, since both s have only one electron. The en- ergy levels of the Be" ion are given by the equation kJ/mole n l, 2, 3 a. Calculate the energies in kl/mole for the four lowest energy levels of the Be" ion. Energy levels of Be ion (En) 21ool ky/male 2100 21ool KT /mole. 21 ool 5.25 D. 525D 21 2335.1 2 Wool E. :1312. le kuumole b One of the most important transitions for the Be" ion involves a jump from the n 2 to the n I n Er s 21 ool LAE for this transition equals Ei Ei.where these two energies are obtained as in Part (a) Find the wavelength in nam of the line emitted when this transition occurs; use value of AE in kJ/mole. Find the Equation 4 to make the calculation. h YID 3xLae mls 5250.2 U- 21001 5250, 2 2100) 1,575X kl/mole, -1.202 yio 1.57 1.575) Y10 Jl male (continued on following page)

Explanation / Answer

Let us check

E4-E1 = 19688.4 KJ /mol

E4-E1 = hc / wavelength

wavelength =

Wavelength = 6.625*10^-34 *3*10^8*6.023*10^23 / 18667.6*10^3

since Energy is given for1mole of electrons .....Avagadro number is used

Wavelength = 6.078 nm

1] 6.078 nm ===> from 4th to 1st level

and next checking

E3 - E1 = 21001 - 2333.4 = 18667.6 KJ /mol

delta E = hc / wavelength

Wavelength = 6.625*10^-34 *3*10^8*6.023*10^23 / 18667.6*10^3

since Energy is given for1mole of electrons .....Avagadro number is used

Wavelength = 6.411 nm

2] 6.411 nm ====> From 3rd state to 1st state

Next checking :

E4 - E3 =1020.8 KJ

wavelength = 117.23 nm

So answer is from 4th state to 3rd state

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