Compound A (C32 H40) decolorizes a solution of bromine in CCl4. Independent anal

Question

Compound A (C32 H40) decolorizes a solution of bromine in CCl4. Independent analysis shows that compound A does not possess any alkynes or phenyl rings. In the presence of Pt and excess H2 compound A undergoes conversion to compound B (C32 H56). How many alkenes does compound A possess?

uestion 4 [1.5 pts) Compound A (cszHa) es a solution of bromine in CCL, Independent analysis shows 4 that compound A does not possess any alkynes or phenyl rings. In the presence of Pt and excess H2 compound A undergoes conversion to compound B (C12Hse). How many alkenes does compound A possess?

Explanation / Answer

A = C32H40

B = C32H56

number hydrogen molecules added to A = 56 - 40 = 16 (8 molecules)

number of hydrogen molecules are added = 8 . this indicates there are total 8 double bonds are present. and

no triple bonds are present mentioned in question.

so number of alkenes = 8

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