Atmospheric 2-butene (C_4H_8) reacts with both the OH radical and ozone via a on
ID: 475830 • Letter: A
Question
Atmospheric 2-butene (C_4H_8) reacts with both the OH radical and ozone via a one step mechanism: C_4H_8 + OH rightarr4ow products k_OH = 6.4 times 10^-11 cm^3 molecule^-1 s^-1 C_4H_8 + O_3 rightarr4ow products k_O3 = 2.4 times 10^-169 cm^3 molecule^-1 s^-1 2-butene reactions via oxidation with OH and O_3 in the atmosphere. The concentration of OH is 2 times 10^6 molecules cm^-3. The mixing ratio of ozone is 120 ppb. Assume that 1 ppb = 2.46 times 10^10 molecules cm^-3. Which reaction is a faster sink of 2-butene? How much faster?Explanation / Answer
reaction rate is given as: -rA = k*CA
=> -rOH = k*COH =6.4*10^-11*2*10^6 =0.000128 molecules/s
=>-rO3 = k*CO3 =2.4*10^-16*120*2.46*10^10=0.00070848 molecules/s
=> -rOH is faster.
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