Pre Lab Questions 1. a. If 6.09 g of sodium chloride are mixed with 35.50gof wat

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Pre Lab Questions 1. a. If 6.09 g of sodium chloride are mixed with 35.50gof water, what is the mass (w/w%) salt in the solution? b. If another solution has a mass of 35.50 g and is made with 6.09 g of sodium chloride, is the mass (ww% of salt the same? Defend your answer. 2. According to the label, a grape soda contains 48 gofsugar per 355 mL serving. If the density of the beverage is 1.052 g/mL, what is the mass (whw%) sugar in the soda? 3. A student prepared a set of solutions of sodium chloride in water as shown in the table below. The masses of the aqueous salt solutions were measured in triplicate for 10.00 mL samples of the salt standards and an unknown commercial beverage. i. Calculate the density of each solution. ii. Use Excel to graph solution density (-axis vs. percent by mass (ww%) salt for the standards and determine the best fit for the data points. Attach this graph to your pre-lab iii. Use the line-of-best-fit to calculate the mass salt in the unknown based on the calculated density and report here: Solution Density, g/mL (average) 0.0% 19.95 10.00 5.21% 10.14 10.00 10.45% 10.34 10.00 14.80% 10,53 10.00 20.05% 0.74

Explanation / Answer

1)

a) if 6.09 g of NaCl is mixed with 35.5 H2O then there will be 6.09 g of NaCl will be in ( 35.5 + 6.09 ) g of solution

so mass% (w/w) of NaCl = (weight of NaCl/weight of solution)*100% = (6.09/41.59)*100% = 0.1464*100% = 14.64%

hence mass % of Nacl = 14.64 %

b) if 6.09 g of NaCl is present in 35.5 g of solution then

mass % of NaCl = (6.09 / 35.5) * 100% = 17.15 % (w/w)

difference between both is we are dissolving NaCl in particular amount of water which will lead to sum up of both weight of NaCl and water to get weight of solution in first case but whereas in second case particular amount of NaCl is made into a particular amount of solution so in which they have given the weight of NaCl and Solution directly.

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