You prepare a solution by adding the following ingredients in the order indicate

Question

You prepare a solution by adding the following ingredients in the order indicated: 600 mL H2O, 125 mL 1.6 M LiCl, 50 mL 20 % (m/v) MgCl2, and 25 mL 10g/L NaCl. The properties of each ingredient are as follows:

LiCl: MW 200g/mole, density 1.2g/mL, density of 1.6 M soln. 1.05g/mL

MgCl2: MW 150g/mole, density 1.3g/mL, density of 20% soln. 1.1g/mL

NaCl: MW 35g/mole, density 1.15g/mL, density of 10g/L soln. 1.03g/mL

Final solution: density: 1.25g/mL

1. What is the final molarity of MgCl2 in the solution?

2. What is the volume in milliliters of one part?

3. What is the percentage (m/m) of NaCl in the final solution?

Explanation / Answer

1. Molarity = moles of solute/ volume in liters

= (50*0.2/1000*95.2)/0.8

= 1.313* 10^-4

the molarity of the MgCL2 would be 1.313* 10^-4

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