The figure below shows a system for cell growth. Reaction in the cell with a rea

Question

The figure below shows a system for cell growth. Reaction in the cell with a reaction rate -r_Glu: C_6H_12O_6 + 1.47O_2 + 0.78 NH_3 rightarrow 0.91 C_4.4 H_7.3 N_0.86 O_1.2 + 3.85 H_2O + 2 CO_2 Three substrates are consumed by the cell: glucose at a flow rate F_glu, o, ammonia at F_NH3, o, oxygen at F_O2.0. They are converted into biomass, carbon dioxide and water, with the conversion reaction listed in the figure and the conversion rate defined by the consumption rate of glucose -r_Glu. Two of these three products are released by the cell: carbon dioxide at F_CO2 and water at F_H2O. The biomass of the cell accumulates as the cell grows. The average molecular formula of the biomass is C_4.4 H_7.3 N_0.86 O_1.2 and the total amount of biomass is N_bio Please use the parameters given above to set up mole balance equations for: glucose the element nitrogen the element oxygen

Explanation / Answer

Mole balance equation for

1.1) Glucose

Rate of Inflow - Rate of outflow + rate of generation = Rate of accumulation

FGlu - 2*FCO2 + 0 = Rate of formation of biomass [dNbio/ dt]

FGlu - 2*FCO2 = 0.91* dNbio/ dt

1.2) Element Nitrogen

Rate of Inflow - Rate of outflow + rate of generation = Rate of accumulation

FNH3 - 0 + 0 = dNbio/ dt

FNH3 = dNbio/ dt

1.3) Element oxygen

1.47 FO2 - 3.85 Fwater - 2 FCO2 = 0.91 dNbio/ dt

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.