Recall the equation: q = s middot m middot Delta T where q is the heat energy, \
ID: 476496 • Letter: R
Question
Recall the equation: q = s middot m middot Delta T where q is the heat energy, "s" is the specific heat of the substance, "m" is the mass of the substance, and Delta T is the change in the temperature. This equation works ONLY when there is no phase change. You use it to find how much energy is required to change the temperature of a certain substance as long as you know the specific heat of the substance and as long as no change in state occurs. Specific Heat Constants Depend on the State of Matter Recall that specific heat is the energy necessary to raise the temperature of one gram of a substance by one degree Celsius. The specific heat of liquid water is a constant equal to 4.18 J/(g- degree C). This means that it takes 4.18 Joules (J) of heat energy to raise the temperature of each gram of water by one degree Celsius. For ice, (he specific heat is 2.06 J/g degree C. Steam's specific heat is 2.02 J/g degree C. You will want to remember the three different specific heat values for H_2O. Calculate a. How much energy is required to heat 44.7g of water from 32 degree C to 88 degree C? b. How many J of energy are needed to heat 72.4g of steam from 120 degree C to 185 degree C?Explanation / Answer
a) q = c × m × T = c × m × (Tfina Tinitial)
= (4.184 J/g °C) × (44.7 g) × (88 32) °C
= (4.184 J/g °C) × (44.7 g) × (56) °C
= 10463.376 J
b) q = c × m × T = c × m × (Tfina Tinitial)
= (2.02 J/g °C) × (72.4g) × (185 120) °C
= (2.02 J/g °C) × (72.4 g) × (65) °C
= 9506.12 J
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