I am not sure if this is right or not and if so is it the expected results as as

Question

I am not sure if this is right or not and if so is it the expected results as asked in question 3?
1. Balance the following reaction equation. I: I NaBr aq. H2SO4 Br 2. Complete the following table, using your actual measured amounts. Greyed-out cells do not need to be filled. MW(g/mol) conc (M) d (g/mL) vol. (mL) mass (mg) mmol equiv 0.810 74.12 1-butanol sulfuric acid sodium bromide 102.89 Water 1-bromobutane 137.02 250.5 1,83 3. Describe the results of your chemical tests: a) Pinkelstein sodium iodidelacerone) test: White .Pwler flekey recipitate (positive No precipitate b) AgNO, test

Explanation / Answer

1-butanol + NaBr / H2SO4 --------> 1-Bromo butane

1 mole of 1-butanol reacts with 1 mole of NaBr and produces 1mole of 1-Bromo butane

So

10.9 mmol of 1-butanol reacts with 10.9 mmol of NaBr and produces 10.9 mmol of 1-bromo butane

Limiting reagent = 1-Butanol

Mass of 1-bromo butane = 10.9*10^-3*137.02 = 1.493 gms [MW of product =137.02]

% yield = Actual yield *100 / Theoritical yield = 0.2505*100 / 1.493 = 16.77 %

3]

The product fromed is 1-bromobutane

AgNO3 rxn with product ---> No precipitate

confirms the presence of Chlorine or bromine

Product with NaI/Acetone ----> white powder flaky precipitate

Confirms the presence of Bromine group

So the product is a bromoalkane

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