Zn(OH) 2 is a sparingly soluble salt. Assuming that [OH - ] = 0.10 M, that this

Question

Zn(OH)2 is a sparingly soluble salt. Assuming that [OH-] = 0.10 M, that this is sufficient for several zinc hydroxide complexes to form, and that each solution is saturated with Zn(OH)2:

Determine the molar solubility of Zn(OH)2 in this scenario.

Determine the concentration of each zinc-containing species in solution.

Zn(OH)2 (s)                Zn(OH)+                      Zn(OH)3-                     Zn(OH)42-

Ksp = 3.0 x 10-16          1 = 2.5 x 104              3 = 7.2 x 1015             4 = 2.8 x 1015

Explanation / Answer

Molar solubility of Zn(OH)2

= 3 x 10^-16/(0.1)^2

= 3.1 x 10^-14 M

concentration of,

Zn(OH)+ = 2.5 x 10^4 x 0.1^2 = 250 M

Zn(OH)3- = 7.2 x 10^15 x 0.1^3 = 7.2 x 10^12 M

Zn(OH)4^2- = 2.8 x 10^15 x (0.1)^4 = 2.8 x 10^11 M

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