Which action would improve the yield of iron in the equilibrium reaction below?

Question

Which action would improve the yield of iron in the equilibrium reaction below? FeO(s) + CO(g) Fe(s) + CO_2(g) Delta H_rxn = -11 kJ mol^-1 removing some CO from the mixture decreasing the volume of the reaction vessel removing some CO_2 from the mixture removing some FeO from the mixture A sample of copper weighing 58.3 grams contains how many copper atoms? 5.5 times 10^24 5.5 times 10^23 6.6 times 10^22 3.9 times 10^22 6.6 times 10^23 A 0.30 M solution of Ca(OH)_2 (aq) is neutralized by adding 35.0 mL of 0.50 M HCl(aq) solution according to the unbalanced equation shown. What is the volume of the original Ca(OH)_2 solution? Ca (OH)_2(aq) + HCl(aq) rightarrow CaCl_2 (aq) + H_2O(l) 10.5mL 15mL 21mL 29mL 58mL.

Explanation / Answer

8. The action that would improve the yield of iron at equilibrium would be,

B. removing some CO2 from the mixture

This is according to the LeChatellier's principle

9. A sample of copper weigh 58.3 g contains copper atoms

= 58.3 x 6.023 x 10^23/63.546

= 5.52 x 10^23

B. 5.5 x 10^23

10. Neutralization of Ca(OH)2 with HCl

moles of HCl used = 0.5 M x 35 ml = 17.5 mmol

moles of Ca(OH)2 present = 17.5/2 = 8.75 mmol

volume of Ca(OH)2 solution present = 8.75 mmol/0.3 M = 29.2 ml

D. 29 ml

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