A stock solution of NaCl made using 25.738g NaCl and diluting to a final volume

Question

A stock solution of NaCl made using 25.738g NaCl and diluting to a final volume of 250.0 mL. What is the molarity of this stock solution? You are the stock solution above to make 3 dilute solutions. Each the new solutions are diluted to a total of 150.0 mL. What is the molarity of each new solution? Calorimetry is a technique used to determine the concentration of many molecules in solution that do not absorb visible light. One example is the detection of glucose in a sample. Glucose itself will not absorb visible light, but forms a blue-green complex when reacted with in acetic acid. The analytical wavelength for this complex is 635 nm. A student prepares the following Beer's Law Plot. Use the plot to answer the following questions.

Explanation / Answer

1. Molarity = moles/volume of solution

molarity of NaCl stock solution = 25.738 g/58.44 g/mol x 0.250 L

= 1.762 M

2. Molaity of dilute solution M2 by using,

M2 = M1V1/V2

V1 and V2 are volume of stock and dilute solution

M1 is molarity of stock solution

So,

dilute solution       Amoun of NaCl stock        molarity of dilute solution (M)

         1                               25                            1.762 x 25/150 = 0.294  

         2                               15                            1.762 x 15/150 = 0.176  

         3                                1                            1.762 x 1/150 = 0.012

  

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