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Q9. Based on the counts shown on the right, what was the growth rate, )., for so

ID: 47839 • Letter: Q

Question

Q9. Based on the counts shown on the right, what was the growth rate, )., for sockeye salmon in the Copper River in Alaska from 2009 to 2010? Q10. What was the growth rate of sockeye salmon in the Copper River between 2006 and 2007? Q11. In 2010, the global human population was estimated to be 6.9 billion and the finite rate of increase (A) was 1.011 per year. What will be the global population size in 2015, using the geometric growth model, assuming A does not change? billion people Summer counts of adult sockeye salmon returning to spawn in the Copper River in Alaska. Data from the Alaska Department of Fish and Game.

Explanation / Answer

9.

Nt = N0 * (lambda)^t

N0 = initial population i.e population at 2009 = 709,330

Nt = population at 2010 = 924,010

So,

924010 = 709,330 * (lambda)^1            Since there is 1 year gap between 2009 and 2010

lambda = 1.303

growth rate = 1.303 per year

10.

Using same logic

N0 = 959,731

Nt = 926,438

So,

926,438 = 959,731 (lambda)^1

lambda = 0.965

So growth rate = 0.965 per year

11.

N0 = 6.9 billion

Nt = N0 * (lambda)^t

Here t = 5 years ( 2015 - 2010 = 5) and lambda = 1.011 per year

Nt = 6.9 billion * (1.011)^5

Nt = 7.29 = 7.3 billion