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For this lab we pipette 50uL from an original 100% 100uL food color concentratio

ID: 478401 • Letter: F

Question

For this lab we pipette 50uL from an original 100% 100uL food color concentration in well A1. Wells B1 to G1 already have 50uL of distilled water in them.We transfer 50uL of the 100% food color from well A1 to B1, mix and then transfer 50uL from B1 to C1 mix and so on until we reach well G1. What is the concentration of the color for each well as it is passed from well to well. I just want to make sure I'm calculating the following concentrations correctly. Thus, from B1 to G1 each should still have it's original volume of 50uL left after 50uL is removed to add to the next well. However, they will have a concentration % of food color from well A that gets more and more dilute.
C1V1 = C2V2
Starting with B1: (100%)(50uL) = (C2)(100uL) = 50% concentration from original 100% from well A
C1: (50%)(50uL) = (C2)(100uL) = 25% concentration from well A
D1: (25%)(50uL) = (C2)(100uL) = 12.5% concentration from well A
E1: (12.5%)(50uL) = (C2)(100uL) = 6.25% concentration from well A
F1: (6.25%)(50uL) = (C2)(100uL) = 3.125% concentration from well A
G1: (3.125%)(50uL) = (C2)(100uL) = 1.56% concentration from well A

Appreciate it!

Explanation / Answer

As we know, the water quanitiy after adding in successive wells increases.

Starting with B1: (100%)(50uL) = (C2)(100uL) = 50% concentration from original 100% from well A

Now when this solution is added in well C1, it has, total water of 100 ul.

So solution total is 150 ul in which 50 ul is Food color and 100 ul is Water

so concentration in C1 = 50/150 = 33%

Similarly

D1 - 50/200 = 25%

E1 - 50/250 = 20%

F1 - 50/300 = 16.66%

G1 - 50/350 = 14.28%

I hope you understood!

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