the equilibrium vapor pressure of water at 30 degrees C is 31.6 torr. when 22.4
ID: 478695 • Letter: T
Question
the equilibrium vapor pressure of water at 30 degrees C is 31.6 torr. when 22.4 g of a nonvolatile nonelectrolyte solute in 50 g of water the vapor pressure of the solution is 2.50 torr lower than that of pure water at 30 degrees C what is the molecular weight of the solute? the equilibrium vapor pressure of water at 30 degrees C is 31.6 torr. when 22.4 g of a nonvolatile nonelectrolyte solute in 50 g of water the vapor pressure of the solution is 2.50 torr lower than that of pure water at 30 degrees C what is the molecular weight of the solute? the equilibrium vapor pressure of water at 30 degrees C is 31.6 torr. when 22.4 g of a nonvolatile nonelectrolyte solute in 50 g of water the vapor pressure of the solution is 2.50 torr lower than that of pure water at 30 degrees C what is the molecular weight of the solute?Explanation / Answer
P° = 31.6 torr pure
m = 22.4 g of x
m = 50 g of water
dP°mix = 2.5
apply:
dP = xsolute* P°solvent pure
2.5 = xsolute*31.6
xsolute = 2.5/31.6 = 0.079113
so...
x solute= mol of solut / total mol
assume...
mol of water = mass/MW = 50/18 = 2.77 mol of water
0.079113 = x / (x+2.77)
where x is mol of solute
solve for x
0.079113x + 2.77*0.079113 = x
(1-0.079113)x = 2.77*0.079113
x = (2.77*0.079113) / (1-0.079113)
x = mol of solut
MW = mass/mol = 22.4/0.23796 = 94.133 g/mol
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.