Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

It is only one question, and the first 4 images are more information to help you

ID: 478797 • Letter: I

Question

It is only one question, and the first 4 images are more information to help you solve the question.

Please I need the answer as soon as possible.

Place a small quantity (about the size of a small pea) of the sodium for potassium salt of each anion into separate small test tubes. Add ten drops of dilute H_2SO_4 to each solid. If a gas is evolved and cautiously smell any gases evolved. Record your observations in Table 1-1. The color change that results from acidifying chromates is dude to the conversation of the yellow CrO_4^-2 to the orange Cr_2 O_7^-2 according to the equilibrium shown in (1). Prepare an aqueous solution of each anion by completely dissolving approximately 50 mg (about the size of a match head) of the sodium or potassium salt of each anion in 4 mL of distilled water. Use 1 mL of this solution for each of the tests in Parts B, C and D. It is best to complete Parts B, C and D for one anion at a time.

Explanation / Answer

3.

a)As per data

CO3 2-   = BaCO3

SO3 2-   = BaSO3

SO4 2-   = BaSO4

PO4 3- = Ba3(PO4)2

CrO4 2- = BaCrO4

formed precipitates.

b)

Dissolved precipitates in dil.HCl were

CO3 2-   = H2CO3 weak acid

SO3 2-   = H2SO3 weak acid

PO4 3- = H3PO4 weak acid

CrO4 2- = H2CrO4 strong acid

c)

SO4 2- does not dissolve in HCl it is derived from strong acid H2SO4.

d)

Salts of weak acid anions dissolve in dil.HCl

e)

AgNO2 = Soluble in dil HCl will give AgCl

PbBr2 = Not soluble

Hg2SO4 = Not soluble

AlPO4 = Soluble

NiCO3 = Soluble

Hg2I2 = Soluble

Cu2S = Slightly soluble

CaF2 = Not soluble (F is electronegative)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote