It is only one question, and the first 4 images are more information to help you
ID: 478797 • Letter: I
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It is only one question, and the first 4 images are more information to help you solve the question.
Please I need the answer as soon as possible.
Place a small quantity (about the size of a small pea) of the sodium for potassium salt of each anion into separate small test tubes. Add ten drops of dilute H_2SO_4 to each solid. If a gas is evolved and cautiously smell any gases evolved. Record your observations in Table 1-1. The color change that results from acidifying chromates is dude to the conversation of the yellow CrO_4^-2 to the orange Cr_2 O_7^-2 according to the equilibrium shown in (1). Prepare an aqueous solution of each anion by completely dissolving approximately 50 mg (about the size of a match head) of the sodium or potassium salt of each anion in 4 mL of distilled water. Use 1 mL of this solution for each of the tests in Parts B, C and D. It is best to complete Parts B, C and D for one anion at a time.Explanation / Answer
3.
a)As per data
CO3 2- = BaCO3
SO3 2- = BaSO3
SO4 2- = BaSO4
PO4 3- = Ba3(PO4)2
CrO4 2- = BaCrO4
formed precipitates.
b)
Dissolved precipitates in dil.HCl were
CO3 2- = H2CO3 weak acid
SO3 2- = H2SO3 weak acid
PO4 3- = H3PO4 weak acid
CrO4 2- = H2CrO4 strong acid
c)
SO4 2- does not dissolve in HCl it is derived from strong acid H2SO4.
d)
Salts of weak acid anions dissolve in dil.HCl
e)
AgNO2 = Soluble in dil HCl will give AgCl
PbBr2 = Not soluble
Hg2SO4 = Not soluble
AlPO4 = Soluble
NiCO3 = Soluble
Hg2I2 = Soluble
Cu2S = Slightly soluble
CaF2 = Not soluble (F is electronegative)
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