Huckel\'s rule, aromaticity help. Thanks guys For each of the species below, ide
ID: 479531 • Letter: H
Question
Huckel's rule, aromaticity help. Thanks guys
For each of the species below, identify any cyclic conjugated system, then: Determine the number of electrons in a system of cyclic conjugation (zero if no cyclic conjugation). Specify whether the species is "a"-aromatic, "aa"-anti-aromatic, or "na"-non-aromatic (neither aromatic nor anti-aromatic) (Presume rings to be planar unless structure obviously prevents planarity. If there is more than one conjugated ring, count electrons in the largest.) Electrons in a cyclic conjugated system. The compound is (a, aa, or na). Electrons in a cyclic conjugated system. The compound is (a, aa, or na) .Explanation / Answer
Q1.
left ring:
2 nitrogens = 2*2 = 4 electrons, then the double bond (which appearst to be in the other ring) = 2
then, other 2*2 = 4, total of 4+2+4 = 10
this is planar, and the ring has all conjugated pi
It is AROMATIC
Q2.
this is planar, so it can't be "Non aromatic"
so... le tus try huckel rule
6 left, 4 in the right
this has 10 electrons
then, this must be aromatic as well
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