Calculate the freezing point and boiling point of each aqueous solution, assumin

Question

Calculate the freezing point and boiling point of each aqueous solution, assuming complete dissociation of the solute. A.Calculate the freezing point of the solution containing 0.116 m K2S. B.Calculate the boiling point of the solution above. C. Calculate the freezing point of the solution containing 21.7 g of CuCl2 in 480 g water. D. Calculate the boiling point of the solution above. E. Calculate the freezing point of the solution containing 7.5 % NaNO3 by mass (in water). F. Calculate the boiling point of the solution above.

Explanation / Answer

A) molality = 0.116 m

delta Tf = i x Kf x m

0 - Tf = 3 x 1.86 x 0.116

Tf = - 0.647 oC

freezing point = - 0.647 oC

B)

delta Tf = i x Kf x m

Tb - 100 = 3 x 0.512 x 0.116

Tb = 100.178 oC

boiling point = 100.178 oC

C)

moles of CuCl2 = 21.7 / 134.45 = 0.1614

molality = 0.1614 / 0.480 = 0.336 m

delta Tf = i x Kf x m

0 - Tf = 3 x 1.86 x 0.336

Tf = - 1.87 oC

freezing point = - 1.87 oC

100 - Tb = 3 x 0.512 x 0.336

Tb = 100.516 oC

boiling point = 100.516 oC

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