Optional extra credit: You are working in an industrial lab and are charged with

Question

Optional extra credit: You are working in an industrial lab and are charged with waste reclamation. The waste that you are working with contains silver chloride and lead (II) chloride. Both compounds are insoluble in cold water; however, lead (II) chloride is soluble in hot water. Your lab is equipped with beakers, stirring rods, filter paper, a hot plate, a suction filtration apparatus, deionizer water, and an oven. a. Write the chemical formulas for silver chloride and lead (II) chloride. b. Propose a procedure for separating these two components. c. After completing the separation, you find out that the percent recovered for one of the components is low. Based on your purposed procedure, briefly explain which component has the low percent recovery and why.

Explanation / Answer

Silver Chloride : AgCl

Lead Chloride : PbCl2.

------------------------------------------

Boil some deionized water in the hot plate . Put the waste mixture in the beaker containing boiling water and stri continuously ---------> filter the solid residue -------> take out the solid and air dry it. this is AgCl------> bring down the filtrate to room temperature--------> solid will start to precipitate (PbCl2)-------> filter to get the solid.

--------------------------------------

Percent recovery of PbCl2 will be less. Even if you cool down the solution, some of it can still be dissolved in water.

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.